[T K]

an array? I have manged to create a program which generates 3 random numbers (luckyNum), then another 3 random numbers (playNum1, 2 and 3).How do I put this into an array so I can sort them into numerical order and see how many of the luckyNum's match the playNum's????? public void jButton1_actionPerformed(ActionEvent e) { luckyNum = 1 + (int)(Math.random()*49); jTextField1.setText(luckyNum+""); luckyNum = 1 + (int)(Math.random()*49); jTextField2.setText(luckyNum+""); luckyNum = 1 + (int)(Math.random()*49); jTextField3.setText(luckyNum+""); } public void jButtonPlay_actionPerformed(ActionEvent e) { playNum1 = 1+(int)(Math.random()*49); playNum2 = 1+(int)(Math.random()*49); playNum3 = 1+(int)(Math.random()*49); luckyNum = new Integer(jTextField1.getText()).intValue(); jTextFieldL1.setText(playNum1+""); jTextFieldL2.setText(playNum2+""); jTextFieldL3.setText(playNum3+"");

[titchyc]

best place to go is W3C

[JavaMan]

ok, this is a bit odd =)
// 3 random numers in an array
double num1 = 1+ Math.round(Math.random()*49);
double num2 = 1+ Math.round(Math.random()*49);
double num3 = 1+ Math.round(Math.random()*49);
double [] luckyNum = new double{num1, num2, num3};
// not sure what the JTextFields are doing there, but....
// to check if they are the same
if(luckyNum[0] == playNum1)
{
System.out.println("They Match!");
}

and goodnight

[mr_miller]

haven't done java commercially for a while but try this....

// Create a list with an ordered list of items
List sortedList = new LinkedList();
sortedList.addAll(Arrays.asList(new double[]{5,1, 13}));

// Search for the random number
int index = Collections.binarySearch(sortedList, 13);

Sorry haven't checked it, done from memory.